Предмет: Химия, автор: Аноним

Рассчитайте количество вещества содержащееся в 5 Г оксида цинка ZnO

Ответы

Автор ответа: ivanovfilipp1

2

Ответ:

0,067 Моль

Объяснение:

Воспользуемся формулой:

n = m/M

n(ZnO) = 5 / 81 = 0,067

Ответ: 0,067 Моль

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