Question

Помогите решить..............

Answer 1

$3\frac12:\left(1\frac4{15}+2\frac9{10}\right)=\boxed{\frac{21}{25}}\\\\1)\;1\frac4{15}+2\frac9{10}=1\frac8{30}+2\frac{27}{30}=(1+2)+\left(\frac8{30}+\frac{27}{30}\right)=3+\frac{35}{30}=3+\frac76=3+1\frac16=4\frac16;\\\\2)\;3\frac12:3\frac16=\frac72:\frac{25}6=\frac72\cdot\frac6{25}=\frac{21}{25}$