Question

Решите пж срочно :
tgx = - (√(3)/3)

Answer 1

$\tan(x) = - \frac{ \sqrt{3} }{3} \\ x = \arctg( - \frac{ \sqrt{3} }{3} ) + \pi n \\ x = - \arctg( \frac{ \sqrt{3} }{3} ) + \pi n \\ x = - \frac{\pi}{6} + \pi n, \: n \in \mathbb Z$