Question

log(3)8-log(3)4+log(3)9/2​

Answer 1

$log_{3}(8) - log_{3}(4) + log_{3}( \frac{9}{2} ) = log_{3}( \frac{8}{4} ) + log_{3}( \frac{9}{2} ) = \\ = log_{3}( \frac{8}{4} \times \frac{9}{2} ) = log_{3}(9) = log_{3}( {3}^{2} ) = 2$

Ответ: 2