Question

Помогите с третьим заданием подобно. pleas

Answer 1

$AB= sqrt{ (3-(-3))^{2} + (0-2)^{2} } = sqrt{36+4} = sqrt{40} =2 sqrt{10}$, $BC= sqrt{ (5-3)^{2} + (4-0)^{2} } = sqrt{4+16} = sqrt{20} =2 sqrt{5}$, $AC= sqrt{ (5-(-3))^{2} + (4-(-2))^{2} } = sqrt{64+36} = sqrt{100} =10$