Question

Срочно помогите !!!!!!!!!!!!!!!!!!!!

Answer 1

Відповідь:

cos²(2α) + ((1 + cos(2α)) * tg(α))² = cos²(2α) + ((1 + 2cos²(α)-1) * sin(α)/cos(α))² = cos²(2α) + ( 2cos²(α) * sin(α)/cos(α))² = cos²(2α) + (2cos(α)*sin(α))² =  cos²(2α) + sin²(2α)

(cos³(α)-(4*cos³(α) - 3cos(α))/ cos(α)  -  (sin³(α) + sin(3α))/ - sin(α) = (-3cos³(α) + 3cos(α))/ cos(α)  +  (sin³(α) + sin(3α))/  sin(α) = -3cos³(α) + (-cos²(α) + 1)/ cos(α)  +  (sin³(α) + sin(3α))/  sin(α) = 3sin²(α) +(sin³(α) + sin(3α)/  sin(α) = 4sin³(α) + sin(3α))/  sin(α)