Question

Решите уравнение
2$2 x^{2} +3x-3= x^{2} -3x+(-2+ x^{2} )$

Answer 1

2x^2  + 3x - 3 = x^2 - 3x + (-2+x^2)
2x^2 + 3x - 3  - x^2 + 3x -(-2+x^2) = 0
x^2  +6x - 3 + 4 - x^2  =0
6x = -1
x = -1/6