Question

Решить неравенство. Даю 50 баллов

Answer 1

$\left | \frac{x^2-3x+2}{x^2+3x+2} \right |\geq 1\\|x^2-3x+2|\geq |x^2+3x+2|,x\neq -2;x\neq -1\\\left ( x^2-3x+2-x^2-3x-2 \right )\left ( x^2-3x+2+x^2+3x+2 \right )\geq 0\\-6x(2x^2+4)\geq 0\Leftrightarrow x(x^2+2)\leq 0\Rightarrow x\leq 0\\x\in \left ( -\infty ;0\right ]\setminus \left \{ -2;-1 \right \}$