Предмет: Химия, автор: badgurll

Mg + O2 =
AL + H2SO4 =
CuO + HNO3 =
Написать переход электронов, определить окислитель и восстановитель.

Ответы

Автор ответа: surkowiw
1

Ответ:

Такая реакция возможна только с концентрированной кислотой:

Cu + 2H2SO4 (конц) = CuSO4 + SO2 + 2H2O

электронный баланс:

Cu(0) - 2e ) = Cu(+2) окисление, восстановитель

S(+6) + 2e = S(+4) восстановление, окислитель

Объяснение:

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