Question

Найдите нули функции: у=2х^2-4х+1

Answer 1

$y=2x^2 -4x+1\\\\2x^2-4x+1=0\\x_{1, 2}=\frac{-(-4)\pm\sqrt{(-4)^2-4*2*1}}{2*2} =[\frac{2-\sqrt{2}}{2};\;\frac{2+\sqrt{2}}{2}]\\\\Otvet: \frac{2-\sqrt{2}}{2};\;\frac{2+\sqrt{2}}{2}.$