Question

Найти производную функции
y=arccos2x+sin5x

Answer 1

$y=arccos2x+sin5x\\\\y'=-\dfrac{1}{\sqrt{1-(2x)^2}}\cdot (2x)'+cos\, 5x\cdot (5x)'=-\dfrac{2}{\sqrt{1-4x^2}}+5\cdot cos\, 5x$