Question

Решите систему уравнений:

1)
2x−3y=16,
x=5.
​
2)
y=2,
3x+4y=11.
​

Answer 1

Ответ:

1) (5; -2)

2) (1; 2)

Объяснение:

$1) \left \{ {{2x-3y=16} \atop {x=5}} \right. \\ \\ \left \{ {{x=5} \atop {2*5-3y=16}} \right. \\ \\ \left \{ {{x=5} \atop {3y=10-16}} \right. \\ \\ \left \{ {{x=5} \atop {y=-2}} \right. \\ \\ (5; -2)$

$2)\left \{ {{y=2} \atop {3x+4y=11}} \right. \\ \\ \left \{ {{y=2} \atop {3x+4*2=11}} \right. \\ \\ \left \{ {{y=2} \atop {3x=11-8}} \right. \\ \\ \left \{ {{y=2} \atop {3x=3}} \right. \\ \\ \left \{ {{y=2} \atop {x=1}} \right. \\ \\ (1; 2)$