Question

 

(4-х)(4+х)=х^2-2
помогите

Answer 1

(4-х)(4+х)=х^2-2
16+4x-4x-x^2=x^2-2
16-x^2=x^2-2
16-x^2-x^2+2=0
16-2x^2+2=0
18-2x^2=0
18=2x^2  /:2
9=x^2  / V
x= 3