Question

Сократите дробь:
Срочно!!!!

Answer 1

Ответ:

$\frac{9a^4b^2-18a^3b^3+9a^2b^2}{18a^2-18b^2} = \frac{9(a^4b^2-2a^3b^3+a^2b^4)}{9(2a^2-2b^2)} = \frac{a^2b^2(a^2-2ab+b^2)}{2(a^2-b^2)} = \frac{a^2b^2(a-b)^2}{2(a-b)(a+b)} = \\ = \frac{a^2b^2(a-b)}{2(a+b)} = \frac{a^3b^2-a^2b^3}{2a+2b}$