Question

х^2-10х+16=0
х^2-х+0, 24=0

Answer 1

x^2-10x+16=0
D=100-64=36>0(2k)
x1=$frac{10+6}{2}$=8
x2=$frac{10-6}{2}$=2

х^2-х+0, 24=0
D=1-0.96=0.4>0(2k)
x1=$frac{1+0.2}{2}$=0.6
x2=$frac{1-0.2}{2}$=0.4