Question

Найти производную функции

Answer 1

$f(x) = ln( {x}^{2} - 2x) \\ f'(x) = ( {x}^{2} - 2x)'( ln(g) )' = (2x - 2) \frac{1}{g} = \\ = \frac{2x - 2}{ {x}^{2} - 2x}$