Question

(m^2+n^2-r^2+2mn)/(m^2-n^2+r^2+2mr)

cократите дробь

Answer 1

$\frac{m^{2}+n^{2}-r^{2} +2mn}{m^{2}-n^{2}+r^{2}+2mr} =\frac{(m^{2}+2mn+n^{2})-r^{2} }{(m^{2}+2mr+r^{2})-n^{2}} =\frac{(m+n)^{2}-r^{2}}{(m+r)^{2}-n^{2}}=\frac{(m+n-r)(m+n+r)}{(m+r-n)(m+r+n)}=\frac{m+n-r}{m+r-n}$

Answer 2

Ответ:

(m+n-r)/(m+r-n)

Объяснение:

(m^2+n^2-r^2+2mn)/(m^2-n^2+r^2+2mr) = (m^2+2mn+n^2-r^2)/(m^2+2mr+r^2-n^2)= ((m+n)^2-r^2))/((m+r)^2-n^2)) = ((m+n)-r)(m+n)+r))/((m+r)-n)(m+r)+n))=(m+n-r)/(m+r-n)