Question

решите уравнение √2sinx+1=0​

Answer 1

Ответ:

$2sin(x) + 1 = 0$

$2sin(x) = -1$

$sin(x) = -\frac{1}{2}$

$x =\frac{7\pi}{6} + 2k\pi$

$x = \frac{11\pi }{6} /6 + 2k\pi$