Question

Помогите пожалуйста решить 265 полностью!

Answer 1

$3\sqrt{20}-\sqrt{5}=3\sqrt{5}\sqrt{2^2}-\sqrt{5}=3\cdot 2\sqrt{5}-\sqrt{5}=6\sqrt{5}-\sqrt{5}=5\sqrt{5}$

$\frac{1}{3}\sqrt{18}+2\sqrt{2}= \frac{1}{3} \cdot 3\sqrt{2}+2\sqrt{2}= \sqrt{2}+2\sqrt{2}=3\sqrt{2}$

$2\sqrt{27}-\sqrt{12}=6\sqrt{3}-2\sqrt{3}=4\sqrt{3}$

$2\sqrt{20}-2\sqrt{45}+\frac{1}{4}\sqrt{16} = 4\sqrt{5}-6\sqrt{5}+1= 1-2\sqrt{5}$

$5\sqrt{8}+\frac{1}{2}\sqrt{2}-2\sqrt{18}=10\sqrt{2}+\frac{1}{2}\sqrt{2}-6\sqrt{2}=4\frac{1}{2}\cdot \sqrt{2}$

$3\sqrt{48}-\sqrt{75}+\frac{1}{7}\sqrt{147} =12\sqrt{3}-5\sqrt{3}+\sqrt{3} = 8\sqrt{3}$