Question

решите и дайте 2 ответа ​

Answer 1

$-6x^2+x+1\geq 0\\\\6x^2-x-1\leq 0\\\\D=25\; ,\; \; x_1=-\frac{1}{3}\; \; ,\; \; x_2=\frac{1}{2}\\\\6(x+\frac{1}{3})(x-\frac{1}{2})\leq 0\\\\znaki:\; \; \; +++[-\frac{1}{3}\, ]---[\; \frac{1}{2}\; ]+++\\\\-\frac{1}{3}\leq x\leq \frac{1}{2}\; \; \; \; \; ili\; \; \; \; \; x\in [-\frac{1}{3}\; ;\; \frac{1}{2}\; ]$