Question

Помогите пж мне срочно нужна ваша помощь,через 10 минут урок ПЖ даю 50 баллов ​

Answer 1

$1)\frac{m^{5}+m^{4}+m^{3}}{m^{3}+m^{2}}*\frac{m^{5}+m^{4}}{m^{4}+m^{3}+m^{2}}=\frac{m^{3}(m^{2}+m+1)}{m^{2}(m+1)}*\frac{m^{4}(m+1)}{m^{2}(m^{2}+m+1)}=\frac{m^{3}*m^{4}}{m^{4}}=m^{3}$

$2)\frac{n^{2}-n^{4}+n^{6}}{1-n}*\frac{n^{2}-1 }{n^{5}-n^{3}+n}=\frac{n^{2}(n^{4}-n^{2}+1) }{1-n}*\frac{(n-1)(n+1)}{n(n^4-n^{2}+1)}}=-\frac{n(n-1)(n+1)}{n-1}=-(n^{2}+n)$

$3)\frac{a-a^{3}}{a^{6}+a^{2}}:\frac{a^{5}-a }{a^{5}+a}=\frac{a(1-a^{2})}{a^{2}(a^{4}+1)}:\frac{a(a^{4}-1)}{a(a^{4}+1)}= \frac{a(1-a^{2}) }{a^{2}(a^{4}+1)} *\frac{a^{4}+1}{(a^{2}-1)(a^{2}+1)}=-\frac{1}{a(a^{2}+1)}$

$4)\frac{9x^{2}-x^{6}}{x^{5}+x^{7}}:\frac{x^{4}-3x^{2}}{x^{9}+x^{7}}=\frac{x^{2}(9-x^{4}) }{x^{5}(1+x^{2})}*\frac{x^{7}(x^{2}+1)}{x^{2}(x^{2}-3)}=\frac{x^{2}(3-x^{2})(x^{2}+3)}{x^{2}-3}=-x^{2}(x^{2}+3)$