Question

$frac{ x^{2-3} }{x+ sqrt{3} }$

Answer 1

$frac{x^{2-3}}{x+sqrt3} =frac{x^{-1}}{x+sqrt3}=frac{1}{x(x+sqrt3)}=frac{1}{x^2+xsqrt3}$

Answer 2

$frac{x^2-3}{x+ sqrt{3} } = frac{x^{-1}}{x+ sqrt{3} } = frac{ frac{1}{x} }{x+ sqrt{3} }= frac{1}{x(x+ sqrt{3}) } = frac{1}{x^2+x sqrt{3} }$