Question

сделайте пожалуйста.​

Answer 1

$25y^2-y^4 = y^2(25 - y^2) = y^2(5-y)(5+y)$

$8xy - 12y - 8x + 12 = 4(2xy - 3y - 2x + 3) = 4(2x - 3)(y - 1)$

$b^2 + 16b + 64 - 49a^2 = (b + 8)^2 - 49a^2 = (b + 8 - 7a)(b + 8 + 7a)$

$(4x+3)(x-1) - (3x-2)(x+2) = 10 - 5x\\\\4x^2-4x + 3x -3 -3x^2 - 6x + 2x + 4 = 10 - 5x\\\\x^2 - x - 3 - 4x + 4 + 5x - 10 = 0\\\\x^2 -9 = 0\\\\x^2 = 9\\\\x_1 = 3\\\\x_2 = -3$

$(4-a)(4+a)^2 = 64-a(a^2+4a - 16)\\\\(4-a)(16 + 8a + a^2) = 64 - a^3 - 4a^2 + 16a\\\\64 + 32a - 4a^2 - 16a - 8a^2 - a^3 = 64 - a^3 - 4a^2 + 16a\\\\64 - 4a^2 + 16a - a^3 = 64 - a^3 - 4a^2 + 16a$