Question

Разложи на множители (c+13d)"2−(13c+d)"2

Answer 1

$(c+13d)^2-(13c+d)^2=\bigg(c+13d-(13c+d))(c+13d+(13c+d)\bigg)=\\\\ =(c+13d-13c-d)(c+13d+13c+d)=(-12c+12d)(14c+14d)=\\\\ =\bigg(-12(c-d)\bigg)\cdot14(c+d)=-12\cdot14(c-d)(c+d)=\\\\ =\bigg{\bold{-168(c-d)(c+d)}}$

Answer 2

Решение ниже в файле