Question

Решите неравенство, пожалуйста.

Answer 1

$(2x-7)^2\geq (6x+1)^2\\\\(2x-7)^2-(6x+1)^2\geq 0\\\\(2x-7-(6x+1))(2x-7+(6x+1))\geq 0\\\\(-4x-8)(8x-6)\geq 0\\\\-4\cdot 2\cdot (x+2)(4x-3)\geq 0\\\\(x+2)(4x-3)\leq 0\\\\x_1=-2\; ,\; \; x_2=\frac{3}{4}\\\\znaki:\; \; \; +++[-2\; ]---[\frac{3}{4}\; ]+++\\\\x\in [-2\, ;\, \frac{3}{4}\; ]$