Question

Выполни умножение: (4v+u2)⋅(16v2−4vu2+u4).

Ответ:
v3
u
.

Answer 1

$\left(4v+u^2\right)\left(16v^2-4vu^2+u^4\right) = \\=4v\cdot \:16v^2+4v\left(-4vu^2\right)+4vu^4+u^2\cdot \:16v^2+u^2\left(-4vu^2\right)+u^2u^4=\\=4\cdot \:16v^2v-4\cdot \:4vvu^2+4vu^4+16v^2u^2-4vu^2u^2+u^4u^2=\\=64v^3-16v^2u^2+4vu^4+16v^2u^2-4vu^4+u^6=\\=64v^3+4vu^4-4vu^4+u^6=\\=64v^3+u^6$