Question

Вказати корені квадратного тричлена.
1) 6; 4
2) 3; 8
3) - 8; - 3
2) 12

Answer 1

${x}^{2} - 11x + 24 = 0 \\d = 121 - 4 \times 1 \times 24 = 121 - 96 = 25 = {5}^{2} \\ x1 = \frac{11 + 5}{2} = 8 \\ x2 = \frac{11 - 5}{2} = 3$

Ответ:2

Answer 2

$x {}^{2} - 11x + 24 = 0 \\ d = {b}^{2} - 4ac \: = 121 - 96 = 25$

$x1 = \frac{ - b + \sqrt{d} }{2a} = 8$

$x2 = \frac{ - b - \sqrt{d} }{2a} = 3$

Ответ : 2).