Question

Помогите срочно с математикой

Answer 1

   $\frac{a^4+4a^2b^2+16b^4}{a^2+2ab+4b^2}=\frac{(a^4+8a^2b^2+16b^4)-4a^2b^2}{a^2+2ab+4b^2}=\frac{(a^2+4b^2)^2-4a^2b^2}{a^2+2ab+4b^2}=$

$=\frac{(a^2+4b^2)^2-(2ab)^2}{a^2+2ab+4b^2}=\frac{(a^2+4b^2-2ab)(a^2+4b^2+2ab)}{a^2+2ab+4b^2}=$  $a^2-2ab+4b^2$