Question

Решите систему неравенств.

Answer 1

решение во вложении

Answer 2

а)

$\left \{ {{x\leq 3} \atop {x>2}} \right.$

x∈(2; 3]

б)

$\left \{ {{3x+12>4x-1} \atop {7-2x\leq 10-3x}} \right. \\\left \{ {{x<13} \atop {x\leq 3}} \right.$

x∈ (-∞ ; 3]

в)

$\left \{ {{3x+8>5x-1} \atop {-\frac{x}{3}<-1 }} \right. \\\left \{ {{x>4,5} \atop {x>3}} \right.$

x∈(3; 4,5)