Question

решите уравнение
(13x-4)(13x+4)-(12x-1)^2-(5x+3)^2=4

Answer 1

$\left(13x-4\right)\left(13x+4\right)-\left(12x-1\right)^2-\left(5x+3\right)^2=4\\169x^2-16-\left(144x^2-24x+1\right)-\left(25x^2+30x+9\right)=4\\=169x^2-16-144x^2+24x-1-25x^2-30x-9=4\\-6x-26=4\\-6x=30\\x=-5$