Question

Помогите пожалуйста
{ 3(х-1)=4y+1
{ 5(y-1)=x+1

Answer 1

$\left \{ {{3(x-1)=4y+1} \atop {5(y-1)=x+1}} \right.\\\\\left \{ {{3x-3=4y+1} \atop {5y-5=x+1}} \right.\\\\\left \{ {{3x-4y=4} \atop {-x+5y=6|*3}} \right.\\\\+\left \{ {{3x-4y=4} \atop {-3x+15y=18}} \right.\\ -------\\11y=22\\\\y=2\\\\x=5y-6=5*2-6=4\\\\Otvet:\boxed{(4;2)}$