Question

Решить 26и27 номера

Answer 1

$26)\; \; \dfrac{(x+2)(x-1)^2}{x-3}<0\\\\znaki:\; \; +++(-2)---(1)---(3)+++\\\\x\in (-2,1)\cup (1,3)\\\\naibolshee\; celoe:\; \; x=2$

$27)\; \; \sqrt{3+2x}=x\; \; ,\; \; ODZ:\; \; \left \{ {{3+2x\geq 0} \atop {x\geq 0}} \right. \; \; \to \; \; \; x\geq 0\\\\3+2x=x^2\\\\x^2-2x-3=0\; \; ,\; \; x_1=-1\; ,\; \; x_2=3\; \; \; (teorema\; Vieta)\\\\x_2=3>0\\\\Otvet:\; \; x=3\; .$