Question

100 балов химия срочно​

Answer 1

Ответ:

22.

дано

V(H2SO4) = 400 mL

p(H2SO4) = 1.1 g/ml

W(H2SO4) = 0.15

+m(H2O) = 60 g

--------------------------

W2(H2SO4) = ?

m(ppa H2SO4) = V(H2SO4) * p(H2SO4) = 400 * 1.1 = 440 g

m(H2SO4) = m(ppa H2SO4) * W(H2SO4) = 440 * 0.15 = 66 g

m( общ ppa H2SO4) = m(ppa H2SO4) + m(H2O) = 440 +60 = 500 g

W2(H2SO4) = m(H2SO4) / m общ (ppa H2SO4) *100% = 66 / 500 * 100% = 13.2%

ответ 13.2 %

23.

дано

m1(ppa AgNO3) = 80 g

W1(AgNO3)  = 10%

m2(ppa AgNO3) = 170 g

W2(AgNO3) = 20%

---------------------------------

W( общ) -?

m1(AgNO3) = 80 * 10% / 100% = 8 g

m2(AgNO3) = 170 * 20% / 100% = 34 g

m общ (AgNO3) = 8+34 = 42 g

m( общ ppa AgNO3)= 80 + 170 = 250 g

W(общ ) = 42 / 250 * 100% = 16.8 %

ответ 16.8%

Объяснение: