Question

(2х-1)(х+5)+5=х(х-2).

Answer 1

$(2x-1)(x+5)+5=x(x-2)\\2x^2+10x-x-5+5=x^2-2x\\x^2+11x=0\\x(x+11)=0\\x=0\: \: \: \: \:x+11=0\\x_1=0\: \: \: \: \:x_2=-11$

Answer 2

(2х-1)(х+5)+5=х(х-2).

2х²+10х-х-5+5=х²-2х

х²+11х=0

х*(х+11)=0

х=0

х=-11