Question

ПЖЖПЖПЖПЖПЖПЖПЖПЖЖЖПЖПЖПЖ

Answer 1

$\Big(\frac{5}{6}-\frac{1}{16}\, m^7\Big)^2=\frac{25}{36}-\frac{5}{48}\, m^7+\frac{1}{256}\, m^{14}$

$\boxed {\; \; (a-b)^2=a^2-2ab+b^2\; \; }$