Question

(x-2)^2+(x-2)(x+2)+4x при х=-0.7

Answer 1

$(x-2)^2+(x-2)(x+2)+4x=x^2-4x+4+x^2-4+4x=2x^2$ при х=-0.7

$2*(-0,7)^2=2*0,49=0,98$