Question

СРОЧНО ПОМОГИТЕ ПО АЛГЕБРЕ!!! ТЕМА ЛОГОРИФМЫ

Answer 1

Ответ:

Объяснение:

$\frac{2*lg(\frac{a+b}{3}) }{lna+lgb} =\frac{lg(\frac{a+b}{3})^{2} }{lna+lgb} =\frac{lg(\frac{a+2ab+b2 }{9}) }{ln(a*b)}=\frac{(lg\frac{a7b+2ab}{9}) }{lg(a*b)} =\frac{(lg\frac{9ab}{9}) }{lg(a*b)} =\frac{lg(a*b)}{lg(a*b)}=1.\\log_ 2}^{2} 12-(log_{2}3+4*log_{2} 3-5)=(log_{2} (3*4))^{2} -(log_{2}x^{2} 3+4*log_{2} 3-5)=\\=(log_{2} 3+log_{2} 4)^{2} -(log_{2}^{2} 3+4*log_{2} 3-5)=\\=log_{2}^{2} 3+2*log_{2} 3*log_{2}4+ log_{2}^{2} 4- (log_{2}^{2} 3 +4*log_{2} 3-5)=$

$=log_{2}^{2} 3+2*2*log_{2} 3+ 2^{2} - log_{2}^{2} 3 -4*log_{2} 3+5=\\=log_{2}^{2} 3+4*log_{2} 3+ 4 - log_{2}^{2} 3 -4*log_{2} 3+5=4+5=9.$