Question

решите систему уравнений
x^2+y^2=97
√xy=6

Answer 1

$x^2+y^2=97\ sqrt{xy}=6\ \ xy=36\ y=frac{36}{x}\ x^2+frac{36^2}{x^2}=97\ x^4-97x^2+1296=0\ x=+-4\ x=+-9\ y=+-4\ y=+-9$