Предмет: Алгебра, автор: dmitrijklackov34

Найдите область определения функции
y=5/sin2x

Ответы

Автор ответа: kybrakdiana2018

0

y=5/sin2x

0=5/sin(2x)

0=5/sin(2x), x≠kπ/2; k € Z

5/sin(2x)=0

5=0 (твердження неправильне)

5 € ∅

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