Question

Решите уравнения:
1) 6х^3 – 24х = 0;
2) 25х^3 – 10х^2 + х = 0.

Answer 1

Ответ:

1)

$6x^{3} -24x=0\\x(6x^{2} -24)=0\\x=0$

или

$6x^{2} -24=0\\6x^{2} =24\\x^{2} =4\\x= +-2$

2)

$25x^{3} -10x^{2} +x=0\\x(25x^{2} -10x+1)=0\\x=0$

или

$25x^{2} -10x+1=0\\D = 100 - 100 = 0\\x = \frac{10}{50} \\x = \frac{1}{5}$