Question

Рівняння8,73/x=45;6y+3,4=38,8

Answer 1

1) $\frac{8,73}{x} =45\\\frac{\frac{873}{100} }{x} =45\\\frac{873}{100x} =45\\873=4500x\\4500x=873\\x=\frac{97}{500} \\x=0,194$

2) $6y+3,4=38,8\\6y=38,8-3,4\\6y=35,4\\y=5,9$