Question

Здравствуйте! Помогите с решением. Заранее благодарю!

Answer 1

$a)\frac{5}{a}=\frac{5(a-b)}{a(a-b)}=\frac{5a-5b}{a^2-ab} \\ \\ \frac{7}{a-b}=\frac{7a}{a(a-b)} =\frac{7a^2}{a^2-ab}$

$c) \frac{14}{a}=\frac{14(a-1)}{a(a-1)}= \frac{14a-14}{a^2-a}\\ \\ \\ \frac{3}{a-1}=\frac{3a}{a^2-a} \\ \\ b)\frac{b}{a+b}=\frac{ab}{a(a+b)}=\frac{ab}{a^2+ab}\\ \\ \frac{b}{a}=\frac{b(a+b)}{a(a+b)}=\frac{b(a+b)}{a(a+b)}=\frac{ab+b^2}{a^2+ab} \\ \\ \\ d)\frac{c}{x}=\frac{c(x+3)}{x(x+3)}$

$a)\frac{1}{8xy}=\frac{3x}{24x^2y}\\ \\ b)\frac{15xz}{120x^3y}=\frac{3z}{24x^2y}\\ \\ c)\frac{2x*8x^2}{3y*8x^2}=\frac{16x^3}{24x^2y}\\ \\ d)\frac{21a^2y^2}{48x^2y^3}=\frac{11.5a^2}{24x^2y}$