Question

Помогите пожалуйста!!!! ​

Answer 1

Ответ:

$\frac{ {x}^{2} - 36}{x + 3} \times \frac{1}{ {x}^{2} + 6x} - \frac{x + 6}{ {x}^{2} - 3x } = \\ = \frac{(x - 6)(x + 6)}{x + 3} \times \frac{1}{x(x + 6)} - \frac{x + 6}{x(x - 3)} = \\ = \frac{x - 6}{x(x + 3)} - \frac{x + 6}{x(x - 3)} = \\ = \frac{(x - 6)(x - 3) - (x + 6)(x + 3)}{x(x - 3)(x + 3)} = \\ = \frac{ {x}^{2} - 9x + 18 - {x}^{2} - 9x - 18}{x(x - 3)(x + 3)} = \\ = \frac{ - 18x}{x( {x}^{2} - 9) } = - \frac{18}{ {x}^{2} - 9 }$