Question

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$1)y = \frac{1}{ \sqrt{x} } \\ \\ 2)y = \tan(x) \\ x = \frac{\pi}{3}$
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Answer 1

$y = \frac{1}{ \sqrt{x} } \\ y' =( {x}^{ - \frac{1}{2} } ) '= - \frac{1}{2} {x}^{ - \frac{3}{2} } = - \frac{1}{2 \sqrt{ {x}^{3} } }$

$y = \tan(x) \\y '( \frac{\pi}{3} ) = ( \tan(x) )' = \frac{1}{ \cos^{2} (x) } = \frac{1}{ \cos^{2} ( \frac{\pi}{3} ) } = \\ = \frac{1}{ \frac{1}{4} } = 4$