Question

Sin750*ctg510+tg(-120)

Answer 1

$sin750ctg510+tg(-120)=\\=sin(360*2+30)ctg(180*3-30)-tg120=\\=sin30(-ctg30)-tg(180-60)=\\= frac{1}{2}*(- sqrt{3} )-(-tg60)=- frac{ sqrt{3} }{2}+ sqrt{3} = frac{-sqrt{3}+2sqrt{3} }{2} = frac{ sqrt{3} }{2}$