Question

Пожалуйста помогите!!! 60 баллов!!! (1 Задание, с решением)

Answer 1

$\frac{ {x}^{2} }{ {(2x + 3)}^{2} } - \frac{3x}{2x + 3} + 2 = 0, \: 2x + 3≠0 \\ \frac{ {x}^{2} }{ {(2x + 3)}^{2} } - \frac{3x(2x + 3)}{ {(2x + 3)}^{2} } + \frac{2(2x +3 ) ^{2} }{ {(2x + 3)}^{2} } = 0 \\ {x}^{2} - 6 {x}^{2} - 9x + 2(4 {x}^{2} + 12x + 9) = 0 \\ - 5 {x}^{2} - 9x + 8 {x}^{2} + 24x + 18 = 0 \\ 3 {x}^{2} + 15x + 18 = 0 \\ {x}^{2} + 5x + 6 = 0, \: x≠ - 1.5 \\ D = {5}^{2} - 4 \times 6 = 1 \\ x_{1} = \frac{ - 5 + 1}{2} = - 2 \\ x_{2} = \frac{ - 5 - 1}{2} = - 3$

Ответ: -3, -2.