Question

Будь ласка зробіть 8)
Благаю

Answer 1

$\left(3x-1\right)\left(3x+1\right)-\left(x-4\right)\left(x-2\right)=0\\9x^2-1-(x^2-6x+8) = 0\\9x^2-1-x^2+6x-8 = 0\\8x^2+6x-9 = 0\\D=6^2-4\cdot 8\cdot (-9) = 36+288 = 324 = 18^2\\x_1=\frac{-6+\sqrt{D}}{2\cdot 8} = \frac{-6+18}{16}= \frac{12}{16}=\frac{3}{4} =0,75 \\x_2=\frac{-6-\sqrt{D}}{2\cdot 8} = \frac{-6-18}{16}= -\frac{24}{16}=-\frac{3}{2} = -1,5$