Question

Найти производную функции:

 

1. $y=3x^{7}-6x^{5}-4x^{2}+17$

2. $y=frac{7x+5}{4-3x}$ 

 3. $y=x^{2}sinx$

 

С решение пжл 

Answer 1

№1. У'=3*7х^6-6*5x^4-4*2x=21х^6-30x^4-8x.

№2. y'=(((7x+5)' * (4-3x))-((7x+5)*(4-3x)' )/((4-3x)^2)=((7*(4-3x))+3*(7x+5))/((4-3x)^2)=

=(28-21x+21x+15)/((4-3x)^2)=43/((4-3x)^2).

№3. y'=2x*sinx+x^2 * cosx

Answer 2

1.

$\y=3x^{7}-6x^{5}-4x^{2}+17\ y'=21x^6-30x^4-8x$

 

2.

$\y=frac{7x+5}{4-3x}\ y'=frac{7(4-3x)-(7x+5)cdot(-3)}{(4-3x)^2}\ y'=frac{28-21x+21x+15}{(4-3x)^2}\ y'=frac{43}{(4-3x)^2}$

 

3.

$\y=x^{2}sin x\ y'=2xsin x+x^2cos x\ y'=x(2sin x+xcos x)$