Question

25 баллов (1/8x^3-7/8)^2

Answer 1

Ответ:

$( \frac{1}{8} x {}^{3} - \frac{7}{8} ) {}^{2} = ( \frac{1}{8} x {}^{3}) {}^{2} - 2 \times \frac{1}{8} x {}^{3} \times \frac{7}{8} +( \frac{7}{8} ) {}^{2} = \frac{1}{64}x {}^{6} - \frac{7}{32} x {}^{3} + \frac{49}{64}$