Question

Решите, пожалуйста, эти два задания

Answer 1

Объяснение:

4. 1)

$\frac{17 {x}^{ - 8} }{14 {y}^{ - 12} } \times \frac{28y}{51 {x}^{ - 21} } = \frac{17 \times 14 \times 2}{14 \times 17 \times 3} \times {x}^{ - 8 + 21} {y}^{1 + 12} = \frac{2}{3} {x}^{13} {y}^{13}$

2)

${( \frac{8 {p}^{ - 4} }{ {q}^{ - 1} } )}^{ - 2} \times {(16 {p}^{ - 6} {q}^{3} )}^{3} = \frac{ {8}^{ - 2} {p}^{- 4 \times (- 2)} }{ {q}^{ - 1 \times ( - 2)} } \times {8}^{6} {p}^{ - 6 \times 3} {q}^{3 \times 3} = \frac{ {8}^{6} {p}^{8} \times {p}^{ - 18} {q}^{9} }{ {8}^{2} {q}^{2} } = {8}^{4} {p}^{8 - 18} {q}^{9 - 2} = \frac{4096 {q}^{7} }{ {p}^{10} }$

5)

$( {a}^{ - 3} + 2)( {a}^{ - 3} - 2) - {( {a}^{ - 3} + 3)}^{2} = {({a}^{ - 3} )}^{2} - {2}^{2} - { ({a}^{ - 3} )}^{2} - 2 \times 3 \times {a}^{ - 3} - {3}^{2} = {a}^{ - 6} - 4 - {a}^{ - 6} - 6 {a}^{ - 3} - 9 = - 13 - 6 {a}^{ - 3}$